7x^2+67x=30

Solution for 7x^2+67x=30 equation:

7x^2+67x=30

We move all terms to the left:

7x^2+67x-(30)=0

a = 7; b = 67; c = -30;
Δ = b2-4ac
Δ = 672-4·7·(-30)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5329}=73$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(67)-73}{2*7}=\frac{-140}{14}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(67)+73}{2*7}=\frac{6}{14}
=3/7
$